hdu 5233 Gunner II (bc #42 B) （离散化）

Posted by 111qqz on Friday, July 31, 2015

Gunner II

**Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 1433    Accepted Submission(s): 540
**

Problem Description

Long long ago, there was a gunner whose name is Jack. He likes to go hunting very much. One day he go to the grove. There are n birds and n trees. The i-th bird stands on the top of the i-th tree. The trees stand in straight line from left to the right. Every tree has its height. Jack stands on the left side of the left most tree. When Jack shots a bullet in height H to the right, the nearest bird which stands in the tree with height H will falls.

Jack will shot many times, he wants to know which bird will fall during each shot.

Input

There are multiple test cases (about 5), every case gives n, m in the first line, n indicates there are n trees and n birds, m means Jack will shot m times.

In the second line, there are n numbers h[1],h[2],h[3],…,h[n] which describes the height of the trees.

In the third line, there are m numbers q[1],q[2],q[3],…,q[m] which describes the height of the Jack’s shots.

Please process to the end of file.

[Technical Specification]

All input items are integers.

1<=n,m<=100000(10^5)

1<=h[i],q[i]<=1000000000(10^9)

Output

For each q[i], output an integer in a single line indicates the id of bird Jack shots down. If Jack can’t shot any bird, just output -1.

The id starts from 1.

Sample Input

5 5
1 2 3 4 1
1 3 1 4 2

Sample Output

1
3
5
4
2

Hint

Huge input, fast IO is recommended.

Source

BestCoder Round #42

http://blog.csdn.net/axuan_k/article/details/45954561

``````/*************************************************************************
> File Name: code/bc/#42/B.cpp
> Author: 111qqz
> Email: rkz2013@126.com
> Created Time: 2015年08月01日 星期六 02时47分54秒
************************************************************************/

#include<iostream>
#include<iomanip>
#include<cstdio>
#include<algorithm>
#include<cmath>
#include<cstring>
#include<string>
#include<map>
#include<set>
#include<queue>
#include<vector>
#include<stack>
#define y0 abc111qqz
#define y1 hust111qqz
#define yn hez111qqz
#define j1 cute111qqz
#define tm crazy111qqz
#define lr dying111qqz
using namespace std;
#define REP(i, n) for (int i=0;i<int(n);++i)
typedef long long LL;
typedef unsigned long long ULL;
const int inf = 0x7fffffff;
const int N=2E5+7;
int n,m;
map<int,int>mp;
set<int>se[N];
int main()
{
while (scanf("%d %d",&n,&m)!=EOF)
{
for ( int i = 1 ; i <= n ; i++ )
se[i].clear();
mp.clear();
int  t = 0;
int x;
for ( int i = 1 ; i <= n ; i++ )
{
scanf("%d",&x);
if (!mp[x]) mp[x]=++t;
se[mp[x]].insert(i);
}
for ( int i = 1 ; i <= m ; i++)
{
scanf("%d",&x);
if (se[mp[x]].size()==0)
{
puts("-1");
}
else
{
printf("%d\n",*se[mp[x]].begin());
se[mp[x]].erase(se[mp[x]].begin());
}
}

}
return 0;
}
``````

``````/*************************************************************************
> File Name: code/bc/#42/BB.cpp
> Author: 111qqz
> Email: rkz2013@126.com
> Created Time: 2015年08月01日 星期六 09时30分45秒
************************************************************************/

#include<iostream>
#include<iomanip>
#include<cstdio>
#include<algorithm>
#include<cmath>
#include<cstring>
#include<string>
#include<map>
#include<set>
#include<queue>
#include<vector>
#include<stack>
#define y0 abc111qqz
#define y1 hust111qqz
#define yn hez111qqz
#define j1 cute111qqz
#define tm crazy111qqz
#define lr dying111qqz
using namespace std;
#define REP(i, n) for (int i=0;i<int(n);++i)
typedef long long LL;
typedef unsigned long long ULL;
const int inf = 0x7fffffff;
map<int,set<int> >mp;
int m,n;
int main()
{
while (scanf("%d %d",&n,&m)!=EOF)
{
mp.clear();
for ( int i = 1;  i <= n ; i++ )
{
int tmpx;
scanf("%d",&tmpx);
mp[tmpx].insert(i);
}
for ( int i = 1 ; i <= m ; i++ )
{
int q;
scanf("%d",&q);
if (mp[q].size()==0)
{
puts("-1");
}
else
{
printf("%d\n",*mp[q].begin());
mp[q].erase(mp[q].begin());
}
}
}

return 0;
}
``````

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